CUET PG 2025 Exam To Take Place From March 13 Till April 1
CUET PG 2025 : The National Testing Agency (NTA) has announced exam dates for the Common University Entrance Test (CUET) PG 2025. Students who applied for the CUET PG 2025 examination can check the exam notice on the official website – exams.nta.ac.in/CUET-PG/. According to the official notification, the NTA will conduct the CUET PG Exam between March 13 to April 1, 2025.
“The registration process for CUET (PG) – 2025 for the Academic Year 2025-26 was open from 02 January to 08 February 2025, followed by a correction window from 10 to 12 February 2025 for necessary modifications. The examination will be conducted in Computer-Based Test (CBT) mode from 13 March to 01 April 2025, across 43 shifts of 90 minutes each,” reads the official notice.
The CUET PG 2025 city intimation slip will be available on the NTA website at nta.ac.in and exams.nta.ac.in/CUET-PG, approximately 10 days before the examination date, the agency said.
The examination will be conducted for 157 subjects for 4,12,024 unique registered candidates. They were allowed to choose up to four test papers/subjects, in line with previous years. The examination will be conducted in Computer-Based Test (CBT) mode for 90 minutes. The medium of the question paper will be English and Hindi (Bilingual) except for languages, M.Tech/Higher Sciences, and Acharya papers (except Hindu Studies, Baudha Dharshan, and Indian Knowledge System).
“The medium of the Question Paper for the CUET (PG) – 2025 will be English and Hindi
(Bilingual) except the following: 41 language papers, M.Tech./Higher Sciences: The papers will be in English only, Acharya Papers: The paper will be in Sanskrit only, except for Indian Knowledge System and Baurdha Darshana, which will be Trilingual (Hindi/Sanskrit/English), Hindu Studies, which will be in Hindi and English,” states the NTA notice.
The CUET PG 2025 exam will retain its 75-question format from the previous year. The marking scheme awards four marks for each correct answer, with a deduction of one mark for every incorrect response.
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